Divisibility Rule of 5
Divisibility Rule of 5
Divisibility Rule of 5:
A number is divisible by 5, if its units digit is 0 or 5.
Justification:
Let n be any natural number. Then, n can be written as
n = 10a + b, where b is the units digit of n
Clearly, 10 is a multiple of 5. Therefore, 10a is also a multiple of 5.
The sum of any two multiples of 5 is a multiple of 5. Therefore, 10a+b will be a multiple of 5, if b is a multiple of 5.
Thus, an integer is divisible by 5, if its units digit is a multiple of 5. That is its units digit is either 0 or 5.
Hence the Test of Divisibility By 5 that is a number is divisible by 5, if its units digit is 0 or 5 is justified.
This implies that if the units digit of a number is not 0 or 5, then it is not divisible by 5.
In the general form since 10a is a multiple of 5. Therefore , when 10a + b is divided by 5, the remainder will be equal to the remainder when n is divided by 5.
Thus, the remainder when an integer is divided by 5 is equal to the remainder when its units digit is divided by 5.
Illustration : Write 521 in the form 10b + a then check its divisibility by 5
Solution: We will express 521 in the form 10b + a
where a = 1 and b = 52.
When 1 is divided by 5 it leaves a remainder as 1, So when 521 is divided by 5, the remainder is 1.
Write 7865 in the form 10b + a then check its divisibility by 5. Find the value of a and b also. | |||
| Right Option : B | |||
| View Explanation | |||
If a number divided by 5 leaves remainder 1, what might be the ones digit of number? | |||
| Right Option : A | |||
| View Explanation | |||
Write 109 in the form 10b + a then check its divisibility by 5. Find the value of a and b also. | |||
| Right Option : D | |||
| View Explanation | |||
Students / Parents Reviews [10]
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